[1873_EASY] Calculate Special Bonus

Table: Employees

+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| employee_id | int     |
| name        | varchar |
| salary      | int     |
+-------------+---------+
employee_id is the primary key for this table.
Each row of this table indicates the employee ID, employee name, and salary.

 

Write an SQL query to calculate the bonus of each employee. The bonus of an employee is 100% of their salary if the ID of the employee is an odd number and the employee name does not start with the character 'M'. The bonus of an employee is 0 otherwise.

Return the result table ordered by employee_id.

The query result format is in the following example.

 

Example 1:

Input: 
Employees table:
+-------------+---------+--------+
| employee_id | name    | salary |
+-------------+---------+--------+
| 2           | Meir    | 3000   |
| 3           | Michael | 3800   |
| 7           | Addilyn | 7400   |
| 8           | Juan    | 6100   |
| 9           | Kannon  | 7700   |
+-------------+---------+--------+
Output: 
+-------------+-------+
| employee_id | bonus |
+-------------+-------+
| 2           | 0     |
| 3           | 0     |
| 7           | 7400  |
| 8           | 0     |
| 9           | 7700  |
+-------------+-------+
Explanation: 
The employees with IDs 2 and 8 get 0 bonus because they have an even employee_id.
The employee with ID 3 gets 0 bonus because their name starts with 'M'.
The rest of the employees get a 100% bonus.

문제 조건 

employee_id가 홀수이고 이름의 첫 번째 글자가 'M'이 아니면 급여의 100%를 보너스로 받고, 그렇지 않을 시 보너스가 없는 형식으로 결과를 출력하시오.

 

문제 풀이

SELECT employee_id,
        CASE WHEN LEFT(name,1) != 'M' AND MOD(employee_id,2) != 0 THEN salary ELSE 0 END AS bonus
FROM Employees 
ORDER BY employee_id