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~고군분투 인생살이~
[문제풀이]184. Department Highest Salary 본문
Table: Employee
+--------------+---------+
| Column Name | Type |
+--------------+---------+
| id | int |
| name | varchar |
| salary | int |
| departmentId | int |
+--------------+---------+
id is the primary key column for this table.
departmentId is a foreign key of the ID from the Department table.
Each row of this table indicates the ID, name, and salary of an employee. It also contains the ID of their department.
Table: Department
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| id | int |
| name | varchar |
+-------------+---------+
id is the primary key column for this table.
Each row of this table indicates the ID of a department and its name.
Write an SQL query to find employees who have the highest salary in each of the departments.
Return the result table in any order.
The query result format is in the following example.
Example 1:
Input:
Employee table:
+----+-------+--------+--------------+
| id | name | salary | departmentId |
+----+-------+--------+--------------+
| 1 | Joe | 70000 | 1 |
| 2 | Jim | 90000 | 1 |
| 3 | Henry | 80000 | 2 |
| 4 | Sam | 60000 | 2 |
| 5 | Max | 90000 | 1 |
+----+-------+--------+--------------+
Department table:
+----+-------+
| id | name |
+----+-------+
| 1 | IT |
| 2 | Sales |
+----+-------+
Output:
+------------+----------+--------+
| Department | Employee | Salary |
+------------+----------+--------+
| IT | Jim | 90000 |
| Sales | Henry | 80000 |
| IT | Max | 90000 |
+------------+----------+--------+
Explanation: Max and Jim both have the highest salary in the IT department and Henry has the highest salary in the Sales department.
# Write your MySQL query statement below
-- From절 서브쿼리
select df.name as department
, e.name as employee
, df.max_sal as salary
from (select d.name, d.id, max(e.salary) as max_sal
from employee as e
inner join department d on e.departmentid = d.id
group by d.name, d.id) AS df
inner join employee as e on e.departmentid = df.id and
e.salary = df.max_sal
-- 다중컬럼 서브쿼리
select d.name as 'department'
, e.name as 'employee'
, salary
from employee e
join department d on e.departmentid = d.id
where (e.departmentid, salary) in (select departmentid, max(salary)
from employee
group by departmentid);
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